X^2+7-2x=17+x

Solution for X^2+7-2x=17+x equation:

X^2+7-2X=17+X

We move all terms to the left:

X^2+7-2X-(17+X)=0

We add all the numbers together, and all the variables

X^2-2X-(X+17)+7=0

We get rid of parentheses

X^2-2X-X-17+7=0

We add all the numbers together, and all the variables

X^2-3X-10=0

a = 1; b = -3; c = -10;
Δ = b2-4ac
Δ = -32-4·1·(-10)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-7}{2*1}=\frac{-4}{2}
=-2
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+7}{2*1}=\frac{10}{2}
=5
$